• Today, 15:25
It's a "rite of passage" for calculus students. (Smile)
3 replies | 22 view(s)
• Today, 12:48
Right. So what that means is that there is no angle $\alpha$ that specifically has $\sin\alpha=\frac 1n$ (rational) and also a rational...
8 replies | 109 view(s)
• Today, 09:04
By that logic that would hold for any angle, wouldn't it? But it doesn't, since with $\alpha=\arctan(3/4)$ both $\cos\alpha$ and $\sin\alpha$ are...
8 replies | 109 view(s)
• Today, 07:20
l will now attempt to, explicitly, complete the demonstration that Df(a) v = \sum_{ 1 \le j \le n } v_j D_j f(a) \ \ \ \ (v \in \mathbb{R}^n ) ...
4 replies | 62 view(s)
• Today, 04:29
Yep. (Nod)
12 replies | 173 view(s)
• Today, 01:11
Here is an attempt to show Df(a) v = \sum_{ 1 \le j \le n } v_j D_j f(a) \ \ \ \ (v \in \mathbb{R}^n ) Now we have ... Df(a) v =...
4 replies | 62 view(s)
• Today, 00:59
Thanks Country Boy ... ... appreciate the help ... Peter
4 replies | 62 view(s)
• Today, 00:54
Thanks GJA ... that was really helpful ... Still reflecting on what you have said ... Thanks again ... Peter
2 replies | 60 view(s)
• Yesterday, 23:26
Here is this week's POTW: Let $ABCD$ be a convex quadrilateral with $\overline{AB}=\overline{AD}$. Let $T$ be a point on the diagonal...
0 replies | 34 view(s)
• Yesterday, 23:21
No one answered this weeks POTW...my solution follows: (a) Apply conservation of angular momentum (subscripts of $R$ pertain to the rod, while...
2 replies | 149 view(s)
• Yesterday, 18:27
Conceptually an integral corresponds to the area under a graph. If that graph extends to infinity, the height of the graph must approach zero, since...
12 replies | 173 view(s)
• Yesterday, 18:06
Erm... then I'm not quite sure what I can use or not. Can you perhaps use the fact that a series $x_1 + x_2 + ...$ can only converge if $x_n \to 0$?...
12 replies | 173 view(s)
• Yesterday, 17:39
What is the regular/basic definition of limits that you are familiar with? The generic definition is the so-called $\varepsilon$-$\delta$...
12 replies | 173 view(s)
• Yesterday, 16:37
The multiplicative inverse of q with respect to q'. That is, it is such that: $$_{q'}^{-1} \cdot q \equiv 1 \pmod {q'}$$ And since $q$ and $q'$...
5 replies | 87 view(s)
• Yesterday, 16:10
Suppose $\lim\limits_{x\to\infty} f(x)=c > 0$. Then for $\varepsilon = \frac c 2 > 0$ there must be some $a$ such that for every $x>a$ we have that...
12 replies | 173 view(s)
• Yesterday, 15:36
Hey MermaidWonders! Let's start with $\int_0^{\infty} f(x)\,dx$, which must also converge. Then $\lim\limits_{{x}\to{\infty}}f(x) = 0$ isn't it?...
12 replies | 173 view(s)
• Yesterday, 15:23
Hi steenis, Suppose $\gcd(m,m')=d$, then we can write $m=qd$ and $m'=q'd$ with $\gcd(q,q')=1$. And suppose $b\equiv b' \pmod d$, so that...
5 replies | 87 view(s)
• Yesterday, 07:38
I am reading "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk ... I am focused on Chapter 2:...
4 replies | 62 view(s)
• Yesterday, 06:50
I am reading "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk ... I am focused on Chapter 2:...
1 replies | 40 view(s)
• Yesterday, 00:31
\frac{5}{4}\cdot\frac{4}{3}=\frac{5}{3} :)
14 replies | 222 view(s)
• February 20th, 2018, 23:10
MarkFL posted a visitor message on Peter's profile
Sometimes editing a thread title is an issue, but the issue is with vBulletin. If you ever want to change a thread title, and can't, just let me know...
• February 20th, 2018, 22:24
Thanks again Krylov .... BUT ... just a comment on D&K's proof .... I have to say that D&K's proof of Hadamard's Lemma though valid, is not...
3 replies | 77 view(s)
• February 20th, 2018, 21:57
I am reading "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk ... I am focused on Chapter 2:...
0 replies | 25 view(s)
• February 20th, 2018, 21:26
I am reading "Multidimensional Real Analysis I: Differentiation" by J. J. Duistermaat and J. A. C. Kolk ... I am focused on Chapter 2:...
2 replies | 60 view(s)
• February 20th, 2018, 20:41
Thanks Krylov, ... followed your advice and obtained the result ... Thanks again ... Peter
3 replies | 77 view(s)
• February 20th, 2018, 17:09
I'm going to walk through this problem, using your substitution...let's begin with: I=\int_{0}^{\Large\frac{3\pi}{4}}\int_{0}^{\pi}\int_{0}^{1}...
14 replies | 222 view(s)
More Activity

### 49 Visitor Messages

1. Hello and welcome back to MHB, ineedhelpnow!

We are happy to see that you have returned, and we look forward to your continued participation here!

On Behalf Of MHB's Staff,

Ackbach.
2. Hello and welcome back to MHB, ineedhelpnow!

We are happy to see that you have returned, and we look forward to your continued participation here!

On Behalf Of MHB's Staff,

Ackbach.
3. Yep. Much better now! Pretty!
4. I only see a dark sinister black rectangle when looking at your avatar.
What happened to the pretty avatar we saw before?
5. Happy Birthday! I hope you had a great day and all your birthday wishes and more come true!
6. Happy birthday!!! I hope everything is going well~
7. Happy Birthday!!! I hope you're having a great time and celebrating with friends and family.
8. Happy Birthday to our pretty girl at MHB! I hope this is the begining of your greatest, most wonderful year ever! May you always be healthy and happy!
9. Happy Birthday!!!!!! May all your wishes come true!!!!!
10. Hello,

Best Regards,

Mark.
Showing Visitor Messages 1 to 10 of 49
Page 1 of 5 123 ... Last
Page 1 of 5 123 ... Last

Date of Birth
July 6
Occupation:
student
Country Flag:
United States

#### Statistics

Total Posts
805
Posts Per Day
0.61
Thanks Given
599
700
##### Visitor Messages
Total Messages
49
Most Recent Message
February 9th, 2017 23:10
##### General Information
Last Activity
February 10th, 2017 11:53
Last Visit
February 10th, 2017 at 00:37
Last Post
February 9th, 2017 at 23:58
Join Date
July 3rd, 2014

### 5 Friends

MHB Master

MHB Seeker

3. #### MarkFLOffline

Pessimist Singularitarian

MHB Master

5. #### Rido12Offline

MHB Journeyman

Showing Friends 1 to 5 of 5