Wouldn't conservation of momentum not work because gravity (on the block) is an external force? Unless of course, the impulse from gravity was accounted for(?)
My attempt:
As I need to find acceleration I believe that I need to use F=ma(and thus draw a free body diagram).
I drew the block's weight components(mgsinθ, mgcosθ) and concluded that the only force acting on the plane in the horizontal direction is the horizontal component of...
Ohhh I see. So if I do the chain rule I would get:
a = mv and then substituting x back:
a = m(mx+b)
a = m^2x + mb
m^2x + mb rules out B and D because x is linear. And rules out C because the y-intercept is nonzero. And rules out A because the slope is nonzero.
Thank you so much!
The answer is E. I was initially very confused as to why the answer was not A but realized that the graph was velocity vs position (rather than velocity vs time) which means I can't simply take the derivative of the given graph.
One thing I tried was writing out the equation first(c being a...
I'm a beginning student who found Physics Forums through generic google searches. The answers here were always very clear and with me getting more and more questions that I get stuck on I thought it'd be a good idea to be able to ask my own questions (and of course, answer the ones I can). See...