The acceleration of the truck if the box is sliding would replace μs with μk in the formula.
As for whether the box will slide, the max force of static friction = μs*N = μs*mg
Plugging that into a = F/m, the maximum acceleration the box can handle without slipping is μs*g.
IF the box is not...
My apologies, I should have been more clear.
When I say the force from kinetic friction on tires for example, I'm referring to the equation: μt * Normal force from the road on the truck
Same with acceleration, I wrote them down as atx, aty, abx, and aby, but I was being lazy with typing the...
So I spoke with my professor, and she basically told me that both static and kinetic friction between the truck and the box can effectively be represented using the same force on the FBD, as long as I note it as such. And since we're only concerned with whether or not the truck will hit the...
I think the box will slip when the acceleration > μsN/m.
Would the kinetic friction force on the box just be facing in the same direction as the static friction force (opposing motion)? But it feels like there would be no forces from kinetic friction until/if the box began to slide, and I'm not...
You’re right. Static friction try to keep the box still with respect to the truck, so it will face the same direction as acceleration (opposite the motion), correct?
Third law, I’m assuming. So the static friction from the box will exert the same force on the truck in the opposite direction...
Homework Statement
A truck (mass M) is carrying a box (mass m) in its flatbed, traveling along a straight, level road at speed v, when the driver sees a deer in the road a distance d ahead. The driver slams on the brakes to cause the truck to skid to a stop. The coefficient of kinetic friction...