• Today, 00:02
You wound up with $x^2\sin(x)$ on the RHS before integrating, but it should be $x\sin(x)$. :)
2 replies | 50 view(s)
• Yesterday, 19:23
When you multiply through by $\mu(x)$, you should have: \frac{d}{dx}(\sin(x)y)=2 And then integrate: \sin(x)y=2x+c_1 ...
2 replies | 35 view(s)
• June 19th, 2018, 19:21
Towards the end, when you divide through by $x$, you want: y(x)=\frac{e^x}{x}+\frac{c}{x} You mistakenly divided the constant by $e^x$.
1 replies | 41 view(s)
• June 19th, 2018, 15:31
Yes, but you used it on the original ODE, not the one in standard linear form. :)
4 replies | 90 view(s)
• June 18th, 2018, 06:19
Thanks steenis ... No worries at all ... Thanks for all your help ... Peter
10 replies | 220 view(s)
• June 18th, 2018, 06:04
Thanks Steenis ... That proof seems really clear ... Will work through it again shortly... Peter
4 replies | 81 view(s)
• June 18th, 2018, 05:18
Sorry Steenis ... I don't understand you ... Can you give me a hint as to what is wrong ...? Peter
10 replies | 220 view(s)
• June 18th, 2018, 04:51
Thanks steenis ... most helpful ... Can see that the short exact sequence $0\rightarrow \text{ker } f \overset{i}{ \rightarrow}R^{(n)}... 10 replies | 220 view(s) • June 18th, 2018, 01:22 ======================================================================== Since I could not see any specific errors, I have completed the proof... 4 replies | 81 view(s) • June 17th, 2018, 12:39 MarkFL replied to a thread [SOLVED] 2.2.3 de with tan x in Differential Equations I can't imagine trying to use the internet on a telephone. I'm sorry scrolling on a telephone is such a chore...they should fix that. 8 replies | 113 view(s) • June 17th, 2018, 05:04 Peter started a thread Deveno ... in Chat Room Deveno is much missed ... especially by those who frequent the Linear and Abstract Algebra Forum ... Deveno's pedagogical abilities were as... 0 replies | 58 view(s) • June 17th, 2018, 04:40 I am reading Dummit and Foote's book: "Abstract Algebra" (Third Edition) ... I am currently studying Chapter 10: Introduction to Module Theory ...... 4 replies | 81 view(s) • June 17th, 2018, 00:59 MarkFL replied to a thread [SOLVED] 2.2.3 de with tan x in Differential Equations Are you using Tapatalk by any chance? I have code in place to let me know when posts have been edited, so I don't miss added content (it's better to... 8 replies | 113 view(s) • June 17th, 2018, 00:52 MarkFL replied to a thread [SOLVED] 2.2.3 de with tan x in Differential Equations When you multiply by$\mu(x)$, you get: \sec(x)y'+\tan(x)\sex(x)y=\sec(x)\sin(2x) This can be written as: ... 8 replies | 113 view(s) • June 16th, 2018, 23:10 Thanks Steenis ... You have shown that$R^{(n)} / N \cong M$where$N = \text{ Ker } f$... ... ... ... ... (1) ... and we have by... 10 replies | 220 view(s) • June 16th, 2018, 19:51 MarkFL replied to a thread [SOLVED] 2.2.3 de with tan x in Differential Equations -\ln(\cos(x))=\ln\left((\cos(x))^{-1}\right)=\ln(\sec(x)) 8 replies | 113 view(s) • June 16th, 2018, 19:38 MarkFL replied to a thread [SOLVED] 2.2.3 de with tan x in Differential Equations \mu(x)=\exp\left(\int \tan(x)\,dx\right)=e^{\Large\ln(\sec(x))}=\sec(x) 8 replies | 113 view(s) • June 16th, 2018, 00:29 300+300\cdot\frac{1666}{100}=300(1+16.66)=300\cdot17.66=5298 Here, we have taken 300, and added 1666% of 300 to it. However if we multiply 300 by... 6 replies | 125 view(s) • June 16th, 2018, 00:03 Thanks steenis ... but not sure if I follow .. ... but will try ... as follows ... We have an epimorphism$f:R^{(n)} \longrightarrow M$... 10 replies | 220 view(s) • June 15th, 2018, 16:28 \mu(x)=\exp\left(\int\frac{1}{x}\,dx\right)=e^{\ln(x)}=x 3 replies | 63 view(s) • June 15th, 2018, 15:53 We can see the integrating factor is$\mu(x)=x$and so the ODE will become: \frac{d}{dx}(xy)=x\sin(x) Upon integrating, we get: ... 3 replies | 63 view(s) • June 15th, 2018, 14:14 That's fine giving$x$as a function of$y$...I just chose to give$y$as a function of$x$since the original equation has$x\$ as the independent...
4 replies | 73 view(s)
• June 15th, 2018, 12:44
We could also simply state: \d{x}{y}=e^y-x \d{x}{y}+x=e^y Now, our integrating factor is: \mu(y)=\exp\left(\int\,dy\right)=e^y
4 replies | 73 view(s)
More Activity

### 3 Visitor Messages

1. Hello and welcome back to MHB, Fallen Angel!

We are happy to see that you have returned, and we look forward to your continued participation here!

On Behalf Of MHB's Staff,

Jameson.
2. Hello Fallen Angel!

As the moderator of the Challenge Problems sub-forum, I want to thank you for posting a challenge for our members to have fun solving with.

Best,

anemone
3. Hello and welcome to MHB, Fallen Angel!

If you have any questions or comments about the forums, please feel free to address them to me or another staff member. We are happy to help and look forward to your participation here!

Best Regards,

Mark.
Showing Visitor Messages 1 to 3 of 3

Age
25
Location:
Cantabria
Country Flag:
Spain

#### Signature

"Poetry is the art of giving different names to the same thing, Mathematics is the art of giving the same name to different things" H. Poincare

"Mathematics is the music of reason" J. J. Sylvester

#### Statistics

Total Posts
205
Posts Per Day
0.15
Thanks Given
39
343
1.673
##### Visitor Messages
Total Messages
3
Most Recent Message
April 30th, 2017 19:45
##### General Information
Last Activity
November 23rd, 2017 13:29
Last Visit
August 31st, 2017 at 23:41
Last Post
October 28th, 2016 at 03:18
Join Date
November 5th, 2014

### 6 Friends

1. #### bwpbruceOffline

MHB Apprentice

2. #### EvobeusOffline

MHB Apprentice

3. #### Fernando RevillaOffline

MHB Journeyman