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• Today, 01:48
Thanks GJA ... Appreciate your help... Peter
2 replies | 32 view(s)
• Yesterday, 23:24
I am reading Paul E. Bland's book "Rings and Their Modules" ... Currently I am focused on Section 3.2 Exact Sequences in \text{Mod}_R ... ... ...
2 replies | 32 view(s)
• April 22nd, 2018, 10:17
MarkFL replied to a thread Olinguito in Introductions
Hello, and welcome to MHB! (Wave)
8 replies | 102 view(s)
• April 21st, 2018, 19:37
THanks for your generous help, steenis... Peter
5 replies | 434 view(s)
• April 21st, 2018, 19:35
Well ... the two standard poodles are intelligent... but quite eccentric ... :) ... Peter
8 replies | 108 view(s)
• April 21st, 2018, 14:15
There was no inconvenience, except to you trying to post and to those trying to read the thread. It was bad coding on my part, done before I knew the...
19 replies | 514 view(s)
• April 20th, 2018, 22:16
Update - Version 1.3.1: Bug fix for usernames with special characters.
2 replies | 224 view(s)
• April 20th, 2018, 19:16
I have added code to that external script so a single quote in a username won't throw an error, and I edited the post so that only the username is...
19 replies | 514 view(s)
• April 20th, 2018, 12:00
Here is this week's POTW: A small bug is placed between two blocks of masses $m_1$ and $m_2$ ($m_1>m_2$) on a frictionless table. A horizontal...
0 replies | 38 view(s)
• April 20th, 2018, 11:59
No one answered this week's problem, and my solution is as follows: A formula for power $P$ we can apply here is: P=\frac{1}{2}\mu\omega^2A^2v...
1 replies | 75 view(s)
• April 20th, 2018, 01:31
I am reading Paul E. Bland's book: Rings and Their Modules and am currently focused on Section 2.2 Free Modules ... ... I need someone to check...
1 replies | 52 view(s)
• April 19th, 2018, 19:58
Quite a coincidence ... :) ... Peter
8 replies | 108 view(s)
• April 19th, 2018, 19:51
My apologies steenis ... I did not read your previous post carefully enough ... and somehow (I don't quite know how ??? ) missed your statement : ...
5 replies | 434 view(s)
• April 19th, 2018, 14:12
You can start with $\alpha^4 = \alpha + 1$, multiply by $\alpha$ and reduce (if necessary). Then repeat the procedure. If in case you don't want to...
3 replies | 97 view(s)
• April 18th, 2018, 23:19
Hi Steenis, Just reworking Section 2.2 of Bland ... and in particular Proposition 2.2.3 ... In the above post you write: "... ... (3) =>...
5 replies | 434 view(s)
• April 18th, 2018, 19:34
Hugo and Pierre are the names of my friends large standard poodles ... Peter
8 replies | 108 view(s)
• April 18th, 2018, 00:57
Seeing that users are having some trouble, I’m giving another week for POTW submissions and corrections. You might find it useful to show first that...
1 replies | 95 view(s)
• April 17th, 2018, 20:55
Hi Steenis ... sorry to be slow in responding ... But Hugo (one of my friends large standard poodles - Hugo and Pierre...) chewed up my glasses...
8 replies | 108 view(s)
• April 16th, 2018, 13:57
Welcome, aadams! (Wave) Your answer to (a) looks fine. To answer part (b), you can compute the powers $\alpha^n$ for $n = 1,2,\ldots, 15$ using...
3 replies | 97 view(s)
• April 15th, 2018, 20:01
Awesome work, as always Chris! (Yes) Using your post, where the base case and induction statement have been given, then the induction step would...
6 replies | 133 view(s)
• April 15th, 2018, 12:02
Here are the choices: A.) \frac{1}{2} B.) \frac{1}{2}-\frac{2^{2006}}{3^{2^{2006}}-1} C.) \frac{1}{2}-\frac{2^{2005}}{3^{2^{2005}}-1} D.)...
6 replies | 133 view(s)
• April 14th, 2018, 23:54
I am reading Paul E. Bland's book: Rings and Their Modules and am currently focused on Section 2.1 Direct Products and Direct Sums ... ... I need...
8 replies | 108 view(s)
• April 14th, 2018, 10:56
The actual sum he's given is: S=\sum_{k=0}^{2006}\left(\frac{2^k}{3^{2^k}+1}\right) And he's given several choices for the result. I was hoping...
6 replies | 133 view(s)
• April 14th, 2018, 10:10
Hello MHB! (Wave) A young man in high school I know has been essentially tasked with finding the following partial sum: ...
6 replies | 133 view(s)
• April 14th, 2018, 06:19
THanks Steenis ... ... well, staying with a friend who doesn't drink ... But had a couple of drinks of whisky and soda last night ... :) ... ...
2 replies | 45 view(s)
• April 14th, 2018, 04:14
I am reading Paul E. Bland's book: Rings and Their Modules and am currently focused on Section 2.1 Direct Products and Direct Sums ... ... I need...
1 replies | 41 view(s)
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#### April 1st, 2018

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Ranks Showcase - 8 Ranks
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Name: MHB Topology and Advanced Geometry Award (2017)
 Issue time: January 21st, 2018 09:44 Issue reason:

Name: MHB Analysis Award (2017)
 Issue time: January 21st, 2018 09:42 Issue reason: Congratulations!

Name: MHB Advanced Algebra Award (2016)
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Name: MHB Topology and Advanced Geometry Award (2015)
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Name: MHB Analysis Award (2015)
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Name: Graduate POTW Award (2014)
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Name: MHB Advanced Algebra Award (2014)
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