right M; a+b=0 because there is no number value
L;-a-3b+c however from the left there is still LT^-1 therefore there is 1L T^-1
T; -2a-2c 1L left over
if I am doing this wrong please advise , the example I have used before was a lot simpler than this where...
dimensional analysis is completely new to me and I am going through the steps correctly , its literally how it ends up with a T^_1 being on one side. The only thing I can determine is that the equation doesn't work at all. If not I am utterly clueless, basically for the equation to work , the L...
so it is ML^-1T^-2 . thanks for your help however, this still honestly doesn't help where I am stuck at, it is still going to be as follows
M^(a+b) L^(-1a+3b+c) T^(-2a+2c)
M; a+b=0
L; -1a+3b+c=1 +T^-1and still there are too many unknowns to do anything with