am i right in thinking v(b) is still 2rt2?
If so..
Fd + mgh + o.5mv^2 (b) = 0.5mv^2 (a)
20x0.2 + 2x9.81x0.4 + 0.5x2x(2rt2)^2 = 0.5x2x(v^2)
so v = 3.98
Im not sure where Iv gone wrong
lol il start again with mgh added in! lol
Fd + mgh + o.5mv^2 (b) = 0.5mv^2 (a)
I don't know how to get d, I just assumed its 0.4 as its the distance it has to travel?
1. Homework Statement
Each of the sliders A and B has a mass of 2 kg and moves with negligible friction in its
respective guide, with y being in the vertical direction (see Figure 3). A 20 N horizontal force
is applied to the midpoint of the connecting link of negligible mass, and the...
Homework Statement
Each of the sliders A and B has a mass of 2 kg and moves with negligible friction in its
respective guide, with y being in the vertical direction (see Figure 3). A 20 N horizontal force
is applied to the midpoint of the connecting link of negligible mass, and the...
Homework Statement
123986[/ATTACH]"]
Homework Equations
H= (NI)/ (2(Pi)r)
V=IR
The Attempt at a Solution
a)
total resitance = 100ohms?
from this would the current be 0.12A
over 1ohm resistor: 0.12V
not sure if this is correct even. Any help would be much appreciated.
Homework Statement
123984[/ATTACH]"]
Homework Equations
H= (NI)/ (2(Pi)r)
V=IR
The Attempt at a Solution
a)
total resitance = 100ohms?
from this would the current be 0.12A
over 1ohm resistor: 0.12V
not sure if this is correct even. Any help would be much appreciated.
Homework Statement
coursework - I will be varying the temperatures of steel ball bearings as they drop onto a metal plate, with the bounce heights, i can work out the coefficient of restitution. however, i need help on the theory behind how temperature will actually effect the coefficient...