Thank you everyone! My answer using method 2 was actually 1000 times larger than the answer using method 1. I guess you have to take into account relativity!
but is the equation correct?
I actually forgot how I got p = sqrt(2Em)...I think I derived it earlier in my work.
Also I asked my friend who is learning this in school and he said that you have to use idea 2 because it is a particle?
I am having trouble deciding when to use which equation.
If you're given the wavelength of a proton, let's say 100 fm, and have to find the kinetic energy of it, how would you do this?
Here are my ideas:
Idea 1: Use lambda = h/p, where p = sqrt(2Em).
Idea 2: Use E=(pc)^2+(mc^2)^2 =...
I don't think I have learned that yet...
is there any way to use the thick lens equation (as I did in my first post)? Or is it incorrect? (also why is it incorrect if it is?_
How do you use snell's law?? Since the surface is not curved, the incident angle (90 degrees) will be the same as the refracted angle (since n1sinx1=n2sinx2)
Snells law would require two bends---the first from ocean to glass and then from glass to air. Thats my reasoning wit using 1.
I tried doing stuff with beams of light, but can't get an answer since the lens is not curved
It is definitely NOT safe to ignore an n.Im fairly confident my dea is...
Thanks Mr. Bridge...long time no see!
I could not find any specifications of the thick lens equation online or in my textbook...I understand it is derived from lensmakers.
I drew a diagram, and light seems to pass through the ocean--to the glass---to the air.
Is my solution correct then? To...
A window of a submarine is 30 cm thick, and is underwater. The index of refraction of the window is 1.65. The index of refraction fo th eocean is 1.35. The index of refraction inside the submarine is 1.00.
A scuba diver is 1 meter away from thw window. Where does his image form?I used n1/d_o...
I'm just wondering generally (as in, a real life application, not textbook problem).
If there hasn't been any work on it, I'll reserve it to study in high school :wink:
OH wait, would it be:
##\tau = IA\times B = IAB\sin (\omega t)##
## I(cd)B\sin\omega t##
Then plug in I from the equation in the original post ? i am fairly confident on this now.
Homework Statement
You have a loop of wire (dimensions c and d) which is oriented vertically on the y-axis (the y-axis splits the rectangle in two equal pieces), and rotates about the y-axis at constant angular ##\omega##. The magnetic field is in the +i direction.
What would be the torqque...