The voltage across the left-most branch is
1/11∙1+13=13 1/11 =13.0909 V
The voltage across the right-most branch is
-5/11∙2+14 =13.0909V
The voltage across the centre is
4/11∙3+12=13.0909V
Homework Statement
a) Calculate the value of the 12V battery
b) Calculate the power dissipated in R_1,R_2 and R.
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Homework Equations
I_1+I_2+I_R=0
The Attempt at a Solution
For the left-hand...
OK this is what i got then
Let p represent the position of the ‘pot’ slider where 0≤p≤1 (i.e. the proportion of the ‘pot’ resistance that is in parallel with the load resistor). For p=0 the slider is at the bottom (minimum resistance) and for p=1 the slider is at the top (maximum resistance)...