Let I be the current through the circuit. The V to the drop at 2R and 6R, so
2RI + 6RI = 80
8RI = 80
RI = 10
For the whole circuit,
U - 3RI - 2RI - 6RI - 4RI = 0
Try to take it from there!
Homework Statement
Homework Equations
Magnetic flux = integral(B dot dA)
line integral(B dot ds) = (u_o)(i_enc) (Ampere's Law)
The Attempt at a Solution
I can't see how Ampere's law applies because all of the magnetic field vectors along the loop will be perpendicular to that stretch of...
Homework Statement
Here is the problem:
Homework Equations
Typical RL circuit equations.
The Attempt at a Solution
My main question with this problem is figuring out what to do with the third resistor, the one on the right. Initially, I thought of using RL circuit equations with the left...
OK, I think it's starting to make sense. The potential across E2 can't change when the switch it closed, so open or closed, I can ignore E1 and R1? Then I use Thevenin?
Can I use a Thevenin approach for a question like this? I'm trying to use information from this website: https://www.allaboutcircuits.com/textbook/direct-current/chpt-16/complex-circuits/
Thanks for all of your help and patience!
Hello! Thanks for the welcome!
I think it will? E1 will push more current to the right of E2?
I tried another approach using Thevenin equivalent circuits. I got E(Thevenin) = 3.33 V and R(Thevenin) = 13.33 ohms. Then I would just use an RC circuit with those values of E and R?
Homework Statement
Homework Equations
For a basic RC circuit during charging:
q = CV(1-e-t/RC)
i = V/R (e-t/RC)
The Attempt at a Solution
I can solve basic RC circuits but this is just out of my realm of understanding. I can also find the max charge of the capacitor. I'm not looking for...