Recent content by crazyog

Oh ok that makes a lot more sense! Thank you so much! You have been a great help :) !

Ok I just realized again haha...my first M is postive and 2nd negative M1=-2/7 M2=-3.216 -0.918=hi/1.5 hi=-1.4 so inverted ok I get the answer! but I don't understand why it is the product why not add together?

Oh I just realized when I find the magnification due to the first lens, and then the second lens, the product of the two gave me the final magnification and I used this with the orginal height to find it to be 1.4 ... why does the product give me the final magnification? and inverted?

Oh ok I think I get it, so since it is the distance from the object to the image I want to add 0.71683 + 0.08+0.5 = 1.3 and the image is to the right thanks! ok now for part b... I know M= -q/p so would I do -0.7168/.22285 = -3.216 and we know the orginal height M=hi/h -3.216=hi/1.5 but the...

Homework Statement A 1.5 cm tall object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. A converging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens. a)What is the location of the final image with respect to the object...

I figured out there was a mistake on the answer sheet and the answer is 20 cm haha thanks anyways

oh ok, i understand now thank you so much for your help! =)

oh ok so (615*10^-9)/(2*1.501) = 2.04*10^-7 Got it! thanks! so the key was that it is constructive interference, which they stated in the problem... is there a way to tell if they don't state it? like if they say they would the find the maximum or minimum, does that refer to constructive and...

and L is the distance from the screen to the slits right? what did I mix up then?

Homework Statement Two slits separated by 2.00x10^-5 are illuminated by light of wavelength 500nm. If the scree is 8.0m from the slits what is the distance between m = 0 and m=1 bright fringes? answer is 10 cm Homework Equations d=m*lambda*L/y (for the short cute..for small angles)...

well they are referring to the benzene so would it be the 1.501 for n. would the equation be t= (lambda)/4*n hm...but I am still not getting the answer?

Homework Statement What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when viewed at normal incidence and illuminated with orange light (lamba = 615 nm)? A glass slide (ng = 1.620) supports the thin film answer= 204 nm...

Homework Statement Two slits are separated by 2.00x10^-5 m. They are illuminated by a wavelength 5.60x10^-7m. If the distance from the slits to the screen is 6.00 m, what is the separation between the central bright fringe and the third dark fringe? Answer: 0.421 m Homework Equations I...

Oh ok so I want to use f = v/wavelength which is also equal to (1/2L)(sqrt(T/mu) can't I set up a ration like F2/F1 = sqrt(T2/T1) I saw this in the book but I was not sure how they reduced this then I et T2 = (523/526)^2T1 T2 =0.989T1 but you want to do 1 - 0.989 (right?) so 0.0114 then...

Homework Statement Two sinusoidal waves in a string are defined by functions y1= (2.00cm)sin(20x-32t) y2=(2.00cm)sin(25x-40t) where y and x are cm and t is sec (a) What is the phase difference between these two waves at the point x = 5 cm and t = 2 s? (b) What is the position x value...