Step 1: Reduce RHS into singletons
F = {AB->C, C->A, BC->D, ACD->B, D->E, D->G, BE->C, CG->B, CG->D, CE->G}
Step 2: Reduce LHS redundant attributes
ACD->B has closure of A: A, C: C,A and D: D,E,G since A is in the closure of C we can remove A from ACD->B making it CD->B no other LHS could be...
Thank you gents!
I=1:5;
J=transpose(1:5);
V=1./(I+J-1)
I think I got it - by transposing one matrix, MATLAB implicitly extends zeros to create a 5x5 matrix before beginning the operation for V=. Then each value starting at 1,1 fills in the matrix, 1 then 0.5 across the first row,
etc.
Thanks!
My first attempt was:
V=zeros(5,5)
a=1;
i=1:5;
j=1:5;
V(i:j)=a./(i+j-1)
I figured to create a 5x5 with zeros and then to return and replace those values with updated values derived from the Hilbert equation as we move through i and j.
This failed with an error of : Unable to perform assignment...
Homework Statement
What is the force on an electron with a velocity v = (2i – 3j) Mms-1 in a magnetic field B = (0.8i +
0.6j – 0.4k) T
Homework Equations
F=qvBsinθ
The Attempt at a Solution
using cross product I got: (1.92i + 1.28j + 5.77k)10^-13 N which is the listed correct answer.
My...
Thanks mate! BTW - if you haven't seen the finale... jumping the shark abit... Still a fan though :-)
Hi CNH, I think I see the error now. The 5I1 should really be just I1 times the 1 ohm resistor. That makes it all work.
Thanks gents!
Homework Statement
In the circuit shown, find (a) the current in each resistors (b)The power dissipated in each resistor.
Homework Equations
V=IR, P=VI, KVL and KCL
The Attempt at a Solution
See attached.
I was going to post this in the main section as its really a question about whether you...
It's a bit tricky. So when calculating capacitance, if we are offered the total area of both plates, we would need to divide by 2?
Here are two sample questions that I have answered correctly according to the answer guide:
A 15-pF capacitor has a potential difference of 1.50 V between its...
Can anyone explain why? Is it possibly because charge migrates to one side with the other side simply being polarized, but not conducting? I seem to recall that there is no flow through the capacitor, rather a push and pull if you will, on either side.
Hello all,
I have a simple question about capacitors. We are learning about them in class and in some questions, I seem to come up with different answers than the solution sets, always by 2. I apparently am using the area of each plate in a capacitor to derive my results.
My question is when...