Use the fact that \frac{1}{k} - \frac{1}{k+1} = \frac{1}{k(k+1)} to show that
n
sigma (\frac{1}{k(k+1)}) = 1- \frac{1}{n+1}
r=1
What do I need to do to solve it?
I'm not exactly sure what the topic is, but this is the part before it.
https://mathhelpboards.com/discrete-mathematics-set-theory-logic-15/geometric-series-24025.html
Given that the sum of the first n terms of series, s, is 9-32-n
show that the s is a geometric progression.
Do I use the formula an = ar n-1? And if so, how do I apply it?