Hello again,
I've got another question that involves symmetrical components, this time I've attempted it.
The Question follows:
1. In a 3 phase circuit with resistance earthed and neutral and Earth fault in phase “A” which produces a fault current of 800 amps.
Load currents may be taken as...
Hello all:)
Have to revive this thread just to clarify a new question:
Now we must answer the same question, but with no Neutral, this was answered without intention in the beginning of the post
I can do the maths involved, but I don't know how the phasors are 180 degrees apart and I don't...
Ah the take home lesson I guess is to "always allocate A B and C to their appropriate phases and you MUST do so" I made Ic = In subconsciously because I thought it would be needed in a Phasor diagram, but these Phasor Diagrams are strictly for Phase A, B and C - something that I wasn't so...
Sorry I've attached Ic as the resultant vector of A + B, it's a terminology error. I'd like to learn more but we don't get enough practice excersizes unfortunately:(
Sorry I made a mistake in the inputting to calculate the symmetrical values.
Start again: the resultant phasor values are (using Badabung's convention):
Ia = 28.75 arg(0)
Ib = 28.75 arg(240)
Ic from Badabung =-14.38+24.9j = 28.75 arg(-60) = 28.75 arg(300) = this is the resultant neutral...
The symmetric components are (if I take 28.75 arg(60)) for this question are:
Zero =19.2 arg(60)
Positive = 19.2 arg(-60)
Negative = 9.58 arg(0)
The symmetric components are (if I take 28.75 arg(240)) for this question are:
Zero = 0
Postive = 0
Negative = 28.8
Interesting differences.
Cheers,
Hello Zoki and Babadag!, Thanks for the help! This was vaguely what I thought I was supposed to do.
I got Zoki's answer of 28.75 ∠60° by converting everything to the complex number and adding, but that's only because I used the convention that all the phase angles are referenced from Phase A...
Hello Zoki85,
Thanks for the reply. I was wondering if we should've considered current flowing to the neutral? would the phase C being broken, cause the load to be unbalanced and because it's (I assume a star connection): would cause current to flow into the neutral?
Cheers,
Ah I ,maybe somehow I've interpreted "phase" as the "line", so the current is simply 230/8 = 28.75 amps.
Indeed It's a typical homework problem, the problem is my course is an online one: they didn't go through the basics as through as I would've liked and we hardly do math problems, so I'm not...