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• Today, 12:50
Unsolved Challenge
Solve for θ in Challenge Questions and Puzzles
Solve for $\theta$ in the diagram below.
1 replies | 29 view(s)
• Yesterday, 14:13
One-to-one function is otherwise called an injection. One-to-one correspondence is called a bijection. It is an injection that is also a surjection....
1 replies | 32 view(s)
• February 23rd, 2018, 17:00
I don't have kids, but I love to tell dad jokes. Does this make me a faux pa? When does a joke become a dad joke? When it is fully groan. The...
59 replies | 9737 view(s)
• February 19th, 2018, 19:54
No the link was meant to be HTTPS. I was thinking that you might have the HTTP site bookmarked and could be posting through that somehow but honestly...
8 replies | 179 view(s)
• February 19th, 2018, 09:17
Hi Joppy, Thank you for pointing this out. It's always good to learn about bugs and try to fix them. This issue is probably connected to a recent...
8 replies | 179 view(s)
• February 17th, 2018, 00:03
Ok I think I understand slightly better. Let's say there are 3 groups to make this simpler and that if you are in these groups you have the...
11 replies | 207 view(s)
• February 16th, 2018, 23:11
I'm just not understanding your question clearly so it's hard for me to try to comment. I know you've spent time explaining but let's start from the...
11 replies | 207 view(s)
• February 15th, 2018, 22:40
Hi jtkerr, Welcome to MHB! :) So you are searching for 1 specific card out of 52 cards without replacement. For the 1st round there are 51...
2 replies | 130 view(s)
• February 14th, 2018, 16:34
But then we could also need to calculate $n^5 \mod{r}$, which is equal to $n^4 \cdot n \mod{r}$. (Worried) So why can we pick $n^2$ as an upper...
96 replies | 1589 view(s)
• February 14th, 2018, 14:29
In line 6, don't we compute at the beginning $n \mod{r}$, then at the second interation $(n \mod r) \cdot (n \mod{r})$, and so on? (Thinking)
96 replies | 1589 view(s)
• February 14th, 2018, 13:25
I have also an other question. It says the following about the algorithm of post #17. Why are the numbers bounded by $n^2$ and not by $n$...
96 replies | 1589 view(s)
• February 11th, 2018, 23:20
Well I read that post and saw the announcement but somehow didn't internalize the improvement. You should be paid by vBulletin for all of the...
8 replies | 237 view(s)
• February 11th, 2018, 23:15
Hi oriz123, Is this a hypothetical question or related to a real life problem? I'm just curious if you can give some more details. In your...
11 replies | 207 view(s)
• February 11th, 2018, 16:31
This is the correct solution. The command \K is undefined. TeX commands usually consist of a backslash followed by letters.
5 replies | 181 view(s)
• February 11th, 2018, 13:06
I'm going to be honest and embarrass myself now. I've used vBulletin for over 10+ years in all forms and I never knew about this. (Blush)...
8 replies | 237 view(s)
• February 7th, 2018, 15:30
Corollary 1.8.10 states the definition of equivalent norms. Two norms $\mu(x)$ and $\nu(x)$ are called equivalent if there exist positive numbers...
2 replies | 87 view(s)
• February 6th, 2018, 22:25
Jameson replied to a thread Power Outage in Chat Room
I hope it comes back quickly! I lost power for around 40 hours last year and I'm ashamed to admit it got me very anxious. I am definitely plugged in...
2 replies | 175 view(s)
• February 6th, 2018, 12:01
Here is this week's POTW: ----- Let $a$ and $b$ be non-zero real numbers such that $a^3+3a^2b^2+b^3=a^3b^3$. Find all the possible values of...
1 replies | 137 view(s)
• February 6th, 2018, 11:55
Congratulations to the following members for their correct solution: (Smile) 1. kaliprasad 2. greg1313 Solution from kaliprasad: By applying...
1 replies | 159 view(s)
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