A 4700 kg truck carrying a 900 kg crate is traveling at 25 m/s to the right along a straight, level road, as shown below.
Suppose the brakes are applied for 3.0s. During this 3.0s the truck travels 55 m.
1. Calculate the acceleration of the truck during the 3.0s interval. (Assume it is...
The vertical motion of an elevator is recorded and a Position vs Time plot is generated. The plot is shown in the image attached.
1. Construct a scale drawing of the associated Velocity vs Time plot complete with axis labels.
2. Calculate the average acceleration for the time interval t...
The figure attached shows two masses held together by a thread on a rod that is rotating about its center with angular velocity w. If the thread breaks, the masses will slide out to the ends of the rod. How will that affect the rod's angular velocity. Will it increase, decrease, or remain...
TT = 1.5 m * 40 N * sin 60 = 1.5 m * 40 N * 0.866 = 51.96 Nm
TJ = 1.5 m * 35.2 N * sin 80 = 1.5 m * 35.2 N * 0.985= 52.008 Nm
So, Tom's going clockwise and Jerry anticlockwise?
(a) 51.96 Nm - 52.008 Nm = -0.048 Nm
(b) 51.96 Nm + 52.008 Nm = 103.968 Nm
Are the right now?
Tom and Jerry both push on the 3 m diameter merry-go-round shown in the figure attached.
(a) If Tom pushes with a force of 40 N and Jerry pushes with a force of 35.2 N, what is the net torque on the merry-go-round?
(b) What is the net torque if Jerry reverses the direction by 180 degrees...
W = mg ---acting downwards
N = Normal Force ---acting upwards opposite to W
A= acceleration --- acting downwards. Looking at the figure, it's clear the car is going downhill. So we can treat it as a circular motion problem?
Option A would best describe the scenario.
Car--Hill--Free body
A car coasts at a constant speed over a circular hill. Which of the free-body diagrams in the figure attached is correct? Explain.
My attempt:
I am thinking B. Since the car is at a constant speed, there's no acceleration. So there is no additional force acting...
And did I mess up + - for 3?
Could it be -50m-100m/5 secs = -150 m/5 secs= -30 m/s^2?
My reason is since the curve is downwards the velocity must be decreasing--so it's -50 m/s at t=35 instead of 50 m/s
Also, I think my original answer to 2. is wrong. Well there's nothing wrong with (0,20), however, (30,45) should be broken down into two parts because the velocity is zero at t=40, which means the cart was at rest for a second?Should I break it into (30,39) and (41,45)? or simply (30,40) and...
@ jackarms You always answer my questions :) Thank you bro.
Anyways, getting back to the question. I calculated the total distance traveled by the cart. So displacement is direction sensitive, so to speak. Would it help if I converted it into a position vs time graph? I don't think it is needed...