As soon as I posted this I remembered that the F is ACTING on MASS. This makes my F = 49N
D'oh!
I'll leave this here I guess.
Plugging in it all worked out smoothly :)
Homework Statement
A very long u-shape conducting wire is placed vertically in a constant magnetic field. The magnetic field is perpendicular to the plane of the wire. The strength of the magnetic field is B = 0.9 tesla. A conducting rod is placed on the wire, as shown in the picture. The...
Homework Statement
What is the electric field at point A in the unit of σ/ε0?
Homework Equations
E=σ/2ε
The Attempt at a Solution
I just want to make sure my thinking behind this is correct.
From the center we have +5σ. To find the A what I did is subtract the other two -σ from...
Thanks for the quick response!
Ok so here's where I am:
I now know that lambda = Q/L so Q = L * (lambda)
So I'm left with
9e9(-9e-6)/(2-.5)^2
This however is not the correct answer...Where can I go from here?
Homework Statement
A charged rod of length L = 1.00 m lies centered on the x-axis as shown. The rod has a linear charge density which varies according to λ = ax where a = −90.0 μC/m.
What is the x component of the electric field at a point on the x-axis a distance of D = 2.00 m from the end...
Homework Statement
The figure shows three very thin parallel planes of charge with equal separation 8 cm between them. The charge density of the middle plane is +4 nC/m2 (nC = "nano Coulomb") and that of the two outer planes is -2nC/m2. Use Gauss's law to solve the following questions. We...
Thank you soooooo much Redbelly98! I can't believe it was that elementary, I had been stuck on this problem for far too long. I really appreciate the great direction.
Thanks for the warm welcome as well!
:approve::approve::approve:
Homework Statement
a cylindrical solid of charge q, radius R, and length H. The Gaussian surface S is a cylindrical shell of radius r and length h, with r < R. Determine the net electric flux given that q = -48Q, R = 4L, H = 3L, r = 2L, and h = 2L (type the integer value, along with the sign...