In going to take the photo, I found the issue. Although the book's diagram shows concentric circles both within and outside of the circular field, and although the labels #1, #2, #3, and #4 seem to correspond to those circles, they actually dont. They actually correspond to very small Farraday...
I'll take a look. My review isn't quite up to modern physics yet. I wish I could find the Feynman lectures (books) on physics. I glanced through them about 50 years ago, but I don't remember anything. I'm not going to shell out the money a copy costs today with no memory of how good they were.
You sound like an expert. What do you do?
On Oct. 1, 2020, I retired from my job as a software engineer, which I'd done for several decades. Before that I was a physicist or engineer at various jobs. I have a BS and MS in physics.
My retirement project is to learn the entirety of physics...
This seems pointless because your answers never address my one and only question. If a fluid which has been enclosed is sprayed out into the air, one cannot claim that the density won't be reduced. Please don't link me to the great library of Alexandria or something. My question is very specific.
A lot of the things you're telling me are new information for me and I appreciate your ongoing effort to help. First of all, though, my question involves only density, not pressure. I don't mean to seem dense (no pun intended), but my intuitive feeling is that in a flowing (or non-flowing)...
Actually, it doesn't look like my book's derivation. I'm hindered somewhat by not being able to write equations here with Tex or Lex or whatever, but as well as I can type it, its:
p1 + 1/2(rho)(v1)^2 = p2 + 1/2(rho)(v2)^2
Note that they use only a single variable, rho, for the density, on...
Let me make a more modest claim - in the book I'm reading, "Physics" by Resnick and Halliday (I don't have it in front of me this moment), they use the Bernoulli equation with the two points chosen being (1) a random place in the section before the nozzle, which I guess is the combustion...
It's certainly greater than the environment, but in every derivation of this type, they assume that it's identical to the pressure in the tank and that's by no means obvious.
If you've seen it, they chose one point in the combustion chamber and the other in the exhaust nozzle. I think they're assuming that we have a gas both places. They say that the pressure in the nozzle is atmospheric pressure, or it you're in outer space, zero. That makes perfect sense...
So, I had the BS and MS in physics. I went to an employment agent and said, "Anything but teaching," so she got me a job as a teacher in a boy's Catholic high school. In less than a year, I left that and got a job with the Westinghouse Steam Turbine Generator Division. They made electrical...