Recent content by BigMan52

Is that the correct methodology?

OK thank you I thought that would be the output for the DC. This is how I calculated the capacitor value: Using C= I/2f*Vr: I= 2 amps f= 2 x 50 Vr = ripple voltage which I calculated by: 0.024 * 12 =0.288 V (rms) converted to peak to peak by 0.288*sqrt2*2 = 0.815 V

Homework Statement Specify ratings and values for the transformer, bridge rectifier and smoothing capacitor for a 230 V unregulated power supply with an output voltage of 12 V, output current of 2 A and a ripple factor of <0.024 Homework Equations V * I V*sqrt 2 C= I/2f*Vr Id=(1+sqrt2)*ILThe...

Thank you very much!

Thank you, yes it does...

Do I multiply or add the voltage gains for each step?

Is this the correct method and answer?

Homework Statement Calculate the voltage gain for each stage and the overall voltage gain. Homework Equations Ao (Gain) = - Rf/R1 3. The Attempt at a Solution [/B] For the first stage I got: Gain = - 15/10 = - 1.5 For stage 2 I got: Gain = -5.13.3 = -1.55 Multiplying the 2 together to get an...

Brilliant, thank you very much for all your help!

OK thank you very much. So here goes: Vx when Vout is -3V: Vb =V4 = 3V Voltage across R1+R2 = Va-Vb = -3-3 = -6V Current I = -6/2000 = -3mA Vx = Vout - (I x R1) = -3 - -3 = 0V Does that mean the upper threshold voltage for this op amp is +3V and the lower threshold voltage is 0V?

OK using basic ohms law: I = 3/1000 = 3mA So voltage dropped across the 1K resistor would be 9mV making Vx =2.991 V?

Would it be: Vx = R1/R1+R2 x Vout = 0.5 x 3 = 1.5V?

Struggling to find the formula I should be using. I think this is a Schmitt Trigger and all calculations I have seen include a third feedback resistor which isn't here.

Sorry yes, I think I may have posted it in the wrong place. First time using this site. I will have a rethink and post it back in the correct section. Thank you very much for your help.

Please can someone tell me if this calculation is correct? Please see attached question. I have used the +/-3V as the saturation voltage and multiplied it by R2/R2+R3 to give me +/-1.5V.