Recent content by beth87

also instead of c in the real exercise there's y upside down λ but if you say that that before was the right solution I trust you... Thanks a lot to everyone :-D I'll let you know

sorry starting from space of column definition

or maybe it's like this [1,3,5]'+[2,4,6]'=c1[1,0,-1]'+c2[0,1,2]' sum of coloumn vectors and it makes c1=3 and c2=7

so the question of the exercise was which are the values of c1 and c2 so the values of c1 are 1 or 2 and the values of c2 are 3 or 4?

this thing seems impossible... consider that we aren't doing this for a maths course but econometrics and we have never done those things in maths before... so if someone could please help us more... we have been thinking about many hours and we aren't sure what we should do about this...

Pleasee

well [1,3,5]' = c1*[1 ; 0 ; -1]' + c2*[0 ; 1 ; 2]' makes c1 =1 c2= 3 and 2c2-c1 = 5 but [2 ; 4 ; 6]' = c1*[1 ; 0 ; -1]' + c2*[0 ; 1 ; 2]' makes c1=2 c2=4 and 2c2-c1=6 so which are the right values of c1 and c2??

[1,3,5] linear combination of [1,0,-1] ? ... mmmm

but we studied linear indipendence

mmm... I think I give up thanks anyway for your help

I tried this: [1 ; 3 ; 5] + [2 ; 4 ; 6] = c1*[1 ; 0 ; -1] + c2*[0 ; 1 ; 2] and the solutions are c1=3 & c2=7 (confirmed by -c1+2c2=11) could it be right?

" ' " is the transposition from row to column vector. So those are column vectors. We are trying.. thanks we'll write you soon

It is similar to my idea but how could i solve a1*[1,3,5]'+a2*[2,4,6]'=c1*[1,0,-1]'+c2*[0,1,2]'... expecially because neither c1,c2 and a1,a2 are known.

Homework Statement If col (A) is column space of A and ker(A) null space of A with ker(A) = {Ax = 0} and ker(A') = {A'y = 0} Homework Equations Consider the (3x2) matrix : A = [1,2 ; 3,4 ; 5,6] (matlab syntax) Show that col(A) = c1 * [1,0,-1]' + c2 * [0,1,2]' The Attempt...