I have the ratio of the two and I have 2F/F
I have the ratio of 2F/F(sqrt(2)) which reduces to the sqrt(2) sorry my computer doesn't show me the mathematical functions. so I put in what I got for distance earlier which is (F/m)*t^2=1/2*sqrt(2)*t^2
I think it is pythagorean theorem for the magnitude of the resultant force of the second case. To solve for the distance I would use the equation D=Vo+1/2at^2 and since the distance is the same I can plug in the distance for the second case
Homework Statement
A space probe has two engines. Each generates the same amount of force when fired, and the directions of these forces can be independently adjusted. When the engines are fired simultaneously and each applies its force in the same direction, the probe, starting from rest...