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• Yesterday, 22:31
Hey Michael, (Wave) Can you elaborate please a bit on what you mean by "AI-assisted" here? Do you mean a program that adapts to how well you are...
1 replies | 23 view(s)
• September 19th, 2018, 22:30
Thanks Steenis ... Working through your updated post now ... Peter
6 replies | 128 view(s)
• September 19th, 2018, 14:50
Most of your more recent questions are from courses I never took, and so I would rather more qualified folks reply. :D
6 replies | 179 view(s)
• September 19th, 2018, 14:20
I apologize for replying to this months later...I was just going through the site looking for loose ends I've left. :)
6 replies | 179 view(s)
• September 19th, 2018, 13:47
To follow up, we may write: \frac{d}{dt}\left(t^{-2}y\right)=t^{-3}\sin(t) This does not lead to the solution given by your textbook. Going by...
6 replies | 179 view(s)
• September 19th, 2018, 13:27
MarkFL replied to a thread Domain...2 in Pre-Calculus
To follow up, we get: (0,1)\,\cup\,(1,\infty)
2 replies | 355 view(s)
• September 18th, 2018, 22:36
To follow up (which is what we're hoping you will do when given help), we find: m_{\overline{AB}}=\frac{3-(-4)}{2-1}=1 ...
4 replies | 90 view(s)
• September 18th, 2018, 16:08
Thanks so so much for your help Steenis ... I have left the state of Tasmania for a trip to the mainland ... will be staying with a friend outside...
6 replies | 128 view(s)
• September 18th, 2018, 06:01
6 replies | 128 view(s)
• September 17th, 2018, 22:38
Unfortunately, I can't help you with your question, but I did want to welcome you back...I happy to hear you have renewed your desire to do some...
1 replies | 76 view(s)
• September 17th, 2018, 14:26
Let's begin by plotting the 3 given points: It appears that $$\overline{AB}$$ and $$\overline{AC}$$ are the legs. Can you show that the...
4 replies | 90 view(s)
• September 17th, 2018, 05:38
Thanks Hugo ... Yes indeed ... pretty complex ... especially considering what is in fact essentially underlying the category theory ... no...
4 replies | 136 view(s)
• September 16th, 2018, 22:02
Yes, I would write: 100\frac{\Delta A}{A}\%=100\frac{1.2b\cdot1.2h-bh}{bh}\%=100(1.2^2-1)\%=44\%
10 replies | 160 view(s)
• September 16th, 2018, 21:54
Taking it from: 2^{\Large\frac{t}{2}}=500 Convert from exponential to logarithmic form: \frac{t}{2}=\log_2(500) ...
10 replies | 161 view(s)
• September 16th, 2018, 15:28
Please wait until you have progress to post, rather than just posting to say you will post later. Such posts needlessly bump threads. ;)
10 replies | 160 view(s)
• September 16th, 2018, 15:18
10 replies | 161 view(s)
• September 16th, 2018, 13:58
As a slightly different way to approach this problem, we can see that working together for 15 hours, the two inlet pipes can fill 8 tanks, and so it...
7 replies | 117 view(s)
• September 16th, 2018, 13:43
For the benefit of others who may read this thread, I will complete the problem. This will make the thread more useful (hint hint). I posted: ...
5 replies | 87 view(s)
• September 16th, 2018, 12:13
I would let $$L$$ be the amount of money Lucy had initially and $$M$$ be the amount of money Mel had initially. From the information given about...
3 replies | 65 view(s)
• September 16th, 2018, 11:53
Can you show what you've tried or your thoughts on how to begin?
2 replies | 52 view(s)
• September 16th, 2018, 11:47
We can see that it is a trapezoid. A formula for the area $$A$$ of a trapezoid is: A=\frac{h}{2}(B+b) where: h is the height (we see is is 5...
5 replies | 87 view(s)
• September 16th, 2018, 11:16
What type of plane figure is the given area?
5 replies | 87 view(s)
• September 15th, 2018, 23:18
Based on what you initially posted, and my reply to it, can you hazard another attempt?
10 replies | 160 view(s)
• September 15th, 2018, 21:02
Set to population equal to the given amount: 1000\cdot2^{\Large\frac{t}{2}}=500000 Divide through by 1000: 2^{\Large\frac{t}{2}}=500 Can...
10 replies | 161 view(s)
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### 15 Visitor Messages

1. Happy birthday, Bacterius!
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3. Happy Birthday, Bacterius!! I hope you have a nice celebration with your close ones. . Thank you for being an active part of MHB!
4. Hey Bacterius, really liked the number theory challenge of yours. I wonder if that's an Olympiad problem. (PS : I have produced somewhat of a solution, but I am not sure if it's correct)
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You are no longer a teenager...it's all downhill from here.
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