I understand based on the equation F = ma that if there is no acceleration, the forces on the object all balance out to 0 in all directions.
What I don't get is for example, slowly lowering a heavy stone slab at a constant velocity v, and raising it way above my head as high as I can at a...
Thanks. After looking into things, I did realize this Single Variable and Multi Variable Calculus courses are essentially Calc 1-3. For some reason, I thought they were labeled Calc 1-3. After looking at my old transcripts, I see it was labeled "Calc 1", "Calc 2", and then I took both...
Ok, so I think I may have found Calc 1 through 3. I believe in some colleges, it's just two courses, single and multivariable calculus, right?
Here are two MIT courses that I think cover it:
Single Variable Calculus...
I'm trying to brush up on my Calc 1-3, and Physics 1-2. I got up to integration in Thomas' Calculus book no problem. The integration part of it is a bit convoluted to me though. So, I'm trying to find opencourseware that I can look at and go at my own pace through it. I have a few sites, but...
Horizontal distance. My error was in assuming the landing height and the launch height were equal, which they are not. Once that was pointed out to me, I saw exactly where I was going wrong and got it no problem from there. I just need to pay closer attention to exactly what is given (and NOT...
Well, I am hoping to click with at least some of them for study groups at times when needed if not anything else. But yea, I'm thinking connecting with most of them would be a challenge.
As far as socializing, maybe I didn't word that well. I don't have a hard time finding women to date...
Yes, I do know I need to learn LaTeX. I did glance at it the other day, but I haven't had the time to delve into it yet, and this weekend I have the kids, so not sure when I can, but I am absolutely planning to learn it.
As far as the final solution, it was actually a lot easier than I first...
I'm making a big life change. Physics has always been a hobby of mine, but going back to college to finish a long overdue degree in physics. I'd love to find some social circles, particularly since I don't have any friends in this area yet.
As far as college, I'm in my 40s, so I'm probably...
Thanks guys, now I see what I was doing wrong. The heights are different for where he launches from and where he lands. I got it now, I appreciate the help!
The angle of 40 degrees I haven't used, but for how I calculated the x and y axis separately based on times and locations, I don't see how it is relevant to either of them, so if you're referring to the angle, I'm not seeing where it is required for how I calculated it above?
With the x axis, I...
Ok, so to start, the easy part, the velocity in the horizontal x direction (vx):
vx = 20m/(2.5s) = 8m/s
So far so good, but then for the vertical y velocity (vy), my answer is different than the book. I use the equation for position in the y direction, set the y value to 0 (the 2.5s it takes...
Thank you for that. Now I see how that works and I get it. I wasn't sure how to do d/dx when it came to the y and y' parts of the equation. The x becoming "1" and the "h" becoming "0" made sense, but now I see with the other two parts, you can use the product rule on them and y' just becomes...
Well, the first time I do, I end up with the dy/dx = (x + h)/(y - k). That's fine, and what they have in the book
However, when I do the 2nd derivative, it makes it sloppy, and I end up with the "(y-k)^2" in the denominator, which is what's causing me to get two possible answers for k
I'm...
I'm at a loss as to how they got to certain steps in the solutions manual. Here's how far I got with this:
Since the circle is tangent to y = x^2 + 1, the slope at (1, 2) is going to be 2, as is the slope of the 2nd derivative of the circle, so then...
The derivative of the circle would be...