$$W = U = \frac{q^2}{2C} =\frac{q q d}{2 \kappa \epsilon_0 A} = \frac{E P}{2}$$
Then , since E is constant we have that :
$$\delta W = \frac{dW}{dP} dP = \frac{E}{2} dP$$.
My question is how can I make this 2 on the denominator disappear in order to obtain the required expression ?
ps : In...
This is exercise 12.1.2 a from Arfken's Mathematical Methods for Physicists 7th edition :Starting from the Laguerre ODE,
$$xy''+(1-x)y'+\lambda y =0$$
obtain the Rodrigues formula for its polynomial solutions $$L_n (x)$$
According to Arfken (equation 12.9 ,chapter 12) the Rodrigues formula...