Once you find the electric field in each dielectric, you can use V=-∫Edl to find the potential for each dielectric. Then using C=Q/V, you can find capacitance. The E field through each plate is just 1/(dielectric constant)*(Efield without dielectric). Each capacitance for me came out to a number...
So I calculated my Er1 and got (sigma)/4Eo(Zvector). If I would replace sigma with q/A, then would I use (1/2)A for A, since Er1 only covers half the area of the capacitor?
Alright so
1) You can find voltage given the electric field by taking the negative of the integral of the electric field from point a to point b. The field is in the z direction, so the voltage shouldn't change if you stay on the plates.
2) If you have the D field, you can take the closed...
This is the problem I'm working on. So far I know:
1. I am assuming the free charge density is +sigma for the top plate and -sigma for the bottom plate.
2. The electric field from the plates goes from top to bottom plate, in the negative z direction.
3. The electric field of the capacitors...