Recent content by Adam Bourque

bring up my post

Homework Statement BTU input: 2.5 MMBtu/hr Annual Gas usage: 8,525 MMBtu Average Natural Gas Cost (Previous 12 months): $7.59/MMBtu Manufacturing Plant – 7am-7pm, 7 days/week, 50 weeks/yr Assembly/warehouse - 7:00am-10:00pm, 7 days/week, 363 days/yr The gas analyzer was used to check the O2...

Hey Greg, can you change my username to Geyser? Thanks much

Homework Statement (Pump Curve given as attachment) [/B] Find the point where the pump is delivering 1,200 gpm at 45 ft of head. I. What is the pump efficiency (read from the pump curve data)? ii. What is the hp delivered to the water? iii. What is the shaft hp required to drive the pump...

Homework Statement Excel Table gives Temperature of Month & Avg NOAAtemp for bill Homework Equations y = mx + b (Assuming) The Attempt at a Solution 1) if we take temp of month as temp, linear model y=-0.1481*temp+124.8. 2) If we take temp for days of bill as temp, y=-0.1466*temp+124.74

I realized this after posting, thanks for the verification though, I wasn't considering the other operations. Do you mind me asking a related question to this Definitely makes a difference getting a different peak power value (maximum), which is now 185.19 versus before at 264.36. So change in...

See that's what I am confused about because the second occurrence of process 2 starts at 1pm-2:30pm so that would just move the occurrence to 2:30pm through 3:15pm which is the same time period for peak/base/intermediate?

Okay I did this using sum function in excel, does put it in better perspective. For b, I found the maximal powers during each period, all are the same before calculating the cost except for peak maximal during winter (does this seem right?) Or am I suppose to exclude the overlapping of the...

(a) So since it is asking for the kWh for the entire day, do I add up all the kW and multiply it by .25 ? (9497.28 * .25) = 2,374.32 (b) I read your response here wrong, I thought you meant during the periods when process 1 & 2 were active for some reason. This makes way more sense, I will...

You made me decide to get a gold membership on this forums with all the useful help you are giving me. Okay so for part (a) I understand what you are saying now, but am still confused. It is a 15 minute interval, so since kWh is in hours I am assuming I have to multiply the average of...

Okay so for part a, I would multiply 9497.28 (total kW) * 24 hours = 227934.72 kWh right? It occurs during peak period for summer and intermediate period for other months. So Summer = $4.55 * 264.34 = 1202.747 Winter = $2.95 * 264.34 = 779.803 Is this correct? & If so how do I go about part...

You raise a good point here, thank you. Firstly, did I do part (a) correctly or do I have to do something for the conversion of kW to kWh (divide by hours?). I found the peak demand in kW to be 264.34, so what do I do from here? Thank you.

Homework Statement EXCEL TABLE AS ATTACHMENT[/B] a.) What is the kWh used for this day? b.) Assuming that this is the peak day for the previous year and TOD rates shown below apply, what is the energy usage and demand charges for this day? c) What would be the change in charges if the second...

Given: Rs = 0.20 Ω R'r = 0.17 Ω Xs = 0.50 Ω X ' r = 0.60 Ω Rc = 200 Ω Xm = 15 Ω Solution: at Nr = 1165, slip = (Ns- Nr)/Ns = 0.02916 ~2.92%slip at Nr = 1195, slip = (Ns- Nr)/Ns = 0.00416 ~0.42%slip Zp = j Xm || ( (R'r / s) + j X'r ) therefore for i) slip s = 0.02916 Zp = 5.2787 <26.36' or 4.7295...