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• Today, 10:02
caffeinemachine replied to a thread Hi everyone! in Introductions
Hey Raisa! I am currently a PhD student in mathematics, but I was also a mechanical engineering undergrad before I switched to math. I would say that...
1 replies | 5 view(s)
• Today, 03:13
Here is this week's POTW: ----- Find the exact value for the real root of the equation $x^3+3x-2=0$. ----- Remember to read the POTW...
0 replies | 27 view(s)
• Today, 02:59
Congratulations to the following members for their correct solution::) 1. kaliprasad 2. lfdahl Honorable mention goes to cmath123, as he has his...
1 replies | 107 view(s)
• Yesterday, 02:29
MarkFL replied to a thread 231.14.88 3d surface in Calculus
Multiplying through by $9+6x-8y$ and distributing the $26$, we obtain -x^2-y^2+z^2=156x-208y+234 -x^2-156x-y^2+208y+z^2=234 ...
3 replies | 53 view(s)
• February 16th, 2017, 20:51
Here is this week's POTW: ----- Prove that there is a constant $C$ such that, if $p(x)$ is a polynomial of degree $2017,$ then \ ----- ...
0 replies | 41 view(s)
• February 15th, 2017, 20:29
You have two points on the graph, so you can compute the slope as follows: m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} Then, you can...
2 replies | 58 view(s)
• February 14th, 2017, 23:47
Yes, the derivative of the function evaluated at the $x$-coordinate of the tangent point will give you the slope $m$ of the tangent line. :)
4 replies | 89 view(s)
• February 14th, 2017, 23:18
The first derivative of a function gives you the slope of the tangent line, not the tangent line itself. Thus,for some function $f(x)$, the tangent...
4 replies | 89 view(s)
• February 14th, 2017, 22:17
Let's try your substitution of: u=x+9\implies du=dx I=\int_9^{18}\frac{(u-9)^3}{u^2}\,du By the binomial theorem: ...
1 replies | 47 view(s)
• February 14th, 2017, 18:27
Okay, I see what you are doing now. Yes, you can do it but I find it to be a bit confusing since you are (temporarily) giving x a value. Since you...
3 replies | 63 view(s)
• February 14th, 2017, 16:48
You aren't setting x to be anything. You have two equations: 1 = 3A - 3B 0 = 5Ax + 5Bx which has to be satisfied by all x. So the second...
3 replies | 63 view(s)
• February 14th, 2017, 12:31
Just to follow up, we left off with: 8-\frac{15000}{x}=5 Arrange as: 3=\frac{15000}{x} Multiply through by \frac{x}{3}\ne0:
2 replies | 100 view(s)
• February 12th, 2017, 22:44
Yes, those are typically how these two metrics for the center of the data are used. So it comes down to how do we define "having outliers"? In real...
7 replies | 149 view(s)
• February 12th, 2017, 00:21
Yes, we use $\LaTeX$ powered by MathJax, which is what you'll find on most other math sites. The only difference is, unlike other sites, we provide...
3 replies | 105 view(s)
• February 11th, 2017, 18:00
Jameson replied to a thread Election in Pre-Algebra and Algebra
Hi there. :) Look at the part in red to start with. This kind of issue comes up a lot with word problems. We know that the ratio of purple...
2 replies | 59 view(s)
• February 11th, 2017, 17:56
Hi rebo1984, What rules and guidelines have you been given to decide? In general I agree with your answers. The median is less sensitive to...
7 replies | 149 view(s)
• February 10th, 2017, 11:34
Let's generalize the method I posted >>>here<<< to reflect a given point $(a,b)$ about the line $y=mx+k$, where ($m\ne0$). We will call the reflected...
3 replies | 112 view(s)
• February 10th, 2017, 10:27
MarkFL replied to a thread Line y = (x/2) + 3 in Pre-Calculus
Another way to show 3 points are collinear is to pick two distinct pairs from the 3 points, and show that the slope between both pairs is the same. :D
2 replies | 55 view(s)
• February 10th, 2017, 06:17
topsquark replied to a thread Chain Rule...Calculus 3 in Calculus
The honeymoon isn't over yet. The partial derivatives act in the same way as the ordinary derivatives. It's just that your course hasn't given you...
9 replies | 122 view(s)
• February 10th, 2017, 06:15
topsquark replied to a thread Line y = (x/2) + 3 in Pre-Calculus
Yes. How do you know that points are on a line? Easy: All points have to satisfy the line equation y = mx + b for some m and b. Start with...
2 replies | 55 view(s)
• February 10th, 2017, 06:09
topsquark replied to a thread Values For m and b in Pre-Calculus
Before you get to that, what does it mean for the points to be symmetric about y = mx + b? -Dan
1 replies | 37 view(s)
• February 10th, 2017, 06:08
What have you tried? -Dan
3 replies | 112 view(s)
• February 10th, 2017, 00:30
MarkFL replied to a thread Square root Convergence in Calculus
To extend the ladder for $\sqrt{k}$, you want: x_{n+1}=x_n+y_n y_{n+1}=x_{n+1}+(k-1)x_n
1 replies | 73 view(s)
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