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    #1
    Evaluate number of real roots of the equation $$x^6-x^5+x^4-x^3+x^2-x+\frac{2}{5} = 0$$

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    #2
    Quote Originally Posted by jacks View Post
    Evaluate number of real roots of the equation $$x^6-x^5+x^4-x^3+x^2-x+\frac{2}{5} = 0$$
    My solution:


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    Last edited by anemone; December 31st, 2016 at 11:22. Reason: Hide the solution

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