Pessimist Singularitarian

#2
November 6th, 2016,
00:55
For each particular number of yes votes, let's say there are $k$ yes votes, and so $9-k$ no votes, we have to compute how many ways there are to choose $k$ from $9$ and then multiply that by the probability for one particular way to make that choice:

$ \displaystyle {9 \choose k}(0.6)^k(0.4)^{9-k}$

And then, calling the event that it passes $X$, to find the probability of $X$ happening, we need to sum these up for $k=5$ to $k=9$:

$ \displaystyle P(X)=\sum_{k=5}^{9}\left({9 \choose k}(0.6)^k(0.4)^{9-k}\right)$