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  1. MHB Apprentice

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    #1
    hello guys,
    i have a question and looking for an answer quickly...

    question;

    prove that,

    Z is a vector.


    thank you.

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    #2
    Quote Originally Posted by rof View Post
    hello guys,
    i have a question and looking for an answer quickly...

    question;

    prove that,

    Z is a vector.


    thank you.
    Hi rof! Welcome to MHB!

    The chi-square distribution is defined as the sum of the squares of p independent standard normal distributions.
    So your proof follows from the definition.

  3. MHB Apprentice

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    #3 Thread Author
    this is the full question paper. (if that helps you to understand the nature of the question)
    the answer i want is to question number 5.



    thank you
    Last edited by MarkFL; August 21st, 2016 at 13:52. Reason: Attach image so it can be seen.

  4. Pessimist Singularitarian
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    #4
    Quote Originally Posted by rof View Post
    this is the full question paper. (if that helps you to understand the nature of the question)
    the answer i want is to question number 5.





    thank you
    That link is broken...and rather than using a free online image hosting service (many of which don't work well), it is better to attach images inline so that everyone can see them and they are not subject to the image hosting service taking them down.

  5. MHB Apprentice

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    Quote Originally Posted by MarkFL View Post
    That link is broken...and rather than using a free online image hosting service (many of which don't work well), it is better to attach images inline so that everyone can see them and they are not subject to the image hosting service taking them down.
    i corrected it by editing the post as soon as i posted it, but somehow editing didnt happen.

    here is the link;


    5th question

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    #6
    Quote Originally Posted by rof View Post
    i corrected it by editing the post as soon as i posted it, but somehow editing didnt happen.

    here is the link;


    5th question
    I went ahead and edited your previous post to attach the image inline.

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    #7
    Quote Originally Posted by rof View Post
    this is the full question paper. (if that helps you to understand the nature of the question)
    the answer i want is to question number 5.

    thank you
    Your vector $\mathbf Z$ consists of $p$ independent standard normal distributions.
    When we calculate the dot product $\mathbf Z' \mathbf Z$, we get the sum of the squares of those $p$ independent standard normal distributions.
    That is a $\chi_p^2$ distribution by definition.

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    #8 Thread Author
    thanks all for taking time to read my question and providing answers.
    good luck to all...

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